Cannot use object of type stdClass as array?

 

563

I get a strange error using json_decode(). It decode correctly the data (I saw it using print_r), but when I try to access to info inside the array I get:

Fatal error: Cannot use object of type stdClass as array in
C:\Users\Dail\software\abs.php on line 108

I only tried to do: $result['context'] where $result has the data returned by json_decode()

How can I read values inside this array?

 

Answer> 

15 Answers

819

Use the second parameter of json_decode to make it return an array:

$result = json_decode($data, true);

 

 

Use the second parameter of json_decode to make it return an array:

$result = json_decode($data, true);

The function json_decode() returns an object by default.

You can access the data like this:

var_dump($result->context);

If you have identifiers like from-date (the hyphen would cause a PHP error when using the above method) you have to write:

var_dump($result->{'from-date'});

If you want an array you can do something like this:

$result = json_decode($json, true);

Or cast the object to an array:

$result = (array) json_decode($json);

You must access it using -> since its an object.

Change your code from:

$result['context'];

To:

$result->context;

 The problem I have is trying to use the property in a conditional if ($result->context = $var)  This causes the property to be set to the var and returns true, no matter. 

92

Have same problem today, solved like this:

If you call json_decode($somestring) you will get an Object and you need to access like $object->key , but if u call json_decode($somestring, true) you will get an dictionary and can access like $array['key']

90

Use true as the second parameter to json_decode. This will decode the json into an associative array instead of stdObject instances:

$my_array = json_decode($my_json, true);

See the documentation for more details.

 

64

It's not an array, it's an object of type stdClass.

You can access it like this:

echo $oResult->context;

More info here: What is stdClass in PHP?

 

20

To get an array as result from a json string you should set second param as boolean true.

$result = json_decode($json_string, true);
$context = $result['context'];

Otherwise $result will be an std object. but you can access values as object.

  $result = json_decode($json_string);
 $context = $result->context;

Read More

 

Cannot use object of type stdClass as array?

 

563

I get a strange error using json_decode(). It decode correctly the data (I saw it using print_r), but when I try to access to info inside the array I get:

Fatal error: Cannot use object of type stdClass as array in
C:\Users\Dail\software\abs.php on line 108

I only tried to do: $result['context'] where $result has the data returned by json_decode()

How can I read values inside this array?

 

Answer> 

15 Answers

819

Use the second parameter of json_decode to make it return an array:

$result = json_decode($data, true);

 

 

Use the second parameter of json_decode to make it return an array:

$result = json_decode($data, true);

The function json_decode() returns an object by default.

You can access the data like this:

var_dump($result->context);

If you have identifiers like from-date (the hyphen would cause a PHP error when using the above method) you have to write:

var_dump($result->{'from-date'});

If you want an array you can do something like this:

$result = json_decode($json, true);

Or cast the object to an array:

$result = (array) json_decode($json);

You must access it using -> since its an object.

Change your code from:

$result['context'];

To:

$result->context;

 The problem I have is trying to use the property in a conditional if ($result->context = $var)  This causes the property to be set to the var and returns true, no matter. 

92

Have same problem today, solved like this:

If you call json_decode($somestring) you will get an Object and you need to access like $object->key , but if u call json_decode($somestring, true) you will get an dictionary and can access like $array['key']

90

Use true as the second parameter to json_decode. This will decode the json into an associative array instead of stdObject instances:

$my_array = json_decode($my_json, true);

See the documentation for more details.

 

64

It's not an array, it's an object of type stdClass.

You can access it like this:

echo $oResult->context;

More info here: What is stdClass in PHP?

 

20

To get an array as result from a json string you should set second param as boolean true.

$result = json_decode($json_string, true);
$context = $result['context'];

Otherwise $result will be an std object. but you can access values as object.

  $result = json_decode($json_string);
 $context = $result->context;

Read More