Fourth normal form (4NF)
- A relation will be in 4NF if it is in Boyce Codd normal form and has no multi-valued dependency.
- For a dependency A → B, if for a single value of A, multiple values of B exists, then the relation will be a multi-valued dependency.
Example
STUDENT
STU_ID | COURSE | HOBBY |
---|---|---|
21 | Computer | Dancing |
21 | Math | Singing |
34 | Chemistry | Dancing |
74 | Biology | Cricket |
59 | Physics | Hockey |
The given STUDENT table is in 3NF, but the COURSE and HOBBY are two independent entity. Hence, there is no relationship between COURSE and HOBBY.
In the STUDENT relation, a student with STU_ID, 21 contains two courses, Computer and Math and two hobbies, Dancing and Singing. So there is a Multi-valued dependency on STU_ID, which leads to unnecessary repetition of data.
So to make the above table into 4NF, we can decompose it into two tables:
STUDENT_COURSE
STU_ID | COURSE |
---|---|
21 | Computer |
21 | Math |
34 | Chemistry |
74 | Biology |
59 | Physics |
STUDENT_HOBBY
STU_ID | HOBBY |
---|---|
21 | Dancing |
21 | Singing |
34 | Dancing |
74 | Cricket |
59 | Hockey |
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