var imageList = [100,200,300,400,500];
var index = imageList.indexOf(200); // 1
You will get -1 if it cannot find a value in the array.
17 December, 2020
what index values are allowed for array in javascript
var imageList = [100,200,300,400,500];
var index = imageList.indexOf(200); // 1
You will get -1 if it cannot find a value in the array.
Seven Four Incorporation would like to develop an application to monitor their product sale for year 2019 and 2020 [closed]
Seven Four Incorporation would like to develop an application to monitor their product sale for year 2019 and 2020 [closed]
Seven Four Incorporation would like to develop an application to monitor their product sale for year 2019 and 2020 [closed]
Seven Four Incorporation would like to develop an application to monitor their product sale for year 2019 and 2020 [closed]
Adding and Printing elements of an array in C
Adding and Printing elements of an array in C
The problem seems to be here:
for (int i=0; i<200; i++){
fscanf(CFG, "%c", &stringCFG[i]);
howManyItems++;
fprintf(output,"%c", stringCFG[i]);
}
This loop always executes 200 times regardless of what is in the file. In other words - the value of howManyItems will be 200 when the loop is done.
You can check that simply by printing howManyItems after the loop, i.e.
printf("After loop, howManyItems=%d\n", howManyItems);
Since you have:
char stringCFG[200];
then
stringCFG[howManyItems]= ','; // bad.. writing to stringCFG[200]
howManyItems++;
stringCFG[howManyItems]= '0'; // bad.. writing to stringCFG[201]
howManyItems++;
...
will write outside of the array. That is undefined behavior.
You need to stop the first loop once the whole file has been read. Something like:
for (int i=0; i<200; i++){
if (fscanf(CFG, "%c", &stringCFG[i]) != 1)
{
// No more data
break;
}
howManyItems++;
fprintf(output,"%c", stringCFG[i]);
}
and all the following loops must then use howManyItems as the upper limit.
Like
for(int i=0; i<howManyItems; i++){
if(stringCFG[i] == '>'){
RHS= 1;
}
...
}
BTW: Since you want to be able to add 4 extra chars, you probably should do:
char stringCFG[200]; --> char stringCFG[200 + 4];
BTW: Hard-coding the value 200 over and over again is bad practice. Instead use a define like:
#define MAX_CHARS 200
and replace all the hard-coded 200 with MAX_CHARS. Then you can adjust the maximum simply by editing one line instead of multiple lines.
Adding and Printing elements of an array in C
Adding and Printing elements of an array in C
The problem seems to be here:
for (int i=0; i<200; i++){
fscanf(CFG, "%c", &stringCFG[i]);
howManyItems++;
fprintf(output,"%c", stringCFG[i]);
}
This loop always executes 200 times regardless of what is in the file. In other words - the value of howManyItems will be 200 when the loop is done.
You can check that simply by printing howManyItems after the loop, i.e.
printf("After loop, howManyItems=%d\n", howManyItems);
Since you have:
char stringCFG[200];
then
stringCFG[howManyItems]= ','; // bad.. writing to stringCFG[200]
howManyItems++;
stringCFG[howManyItems]= '0'; // bad.. writing to stringCFG[201]
howManyItems++;
...
will write outside of the array. That is undefined behavior.
You need to stop the first loop once the whole file has been read. Something like:
for (int i=0; i<200; i++){
if (fscanf(CFG, "%c", &stringCFG[i]) != 1)
{
// No more data
break;
}
howManyItems++;
fprintf(output,"%c", stringCFG[i]);
}
and all the following loops must then use howManyItems as the upper limit.
Like
for(int i=0; i<howManyItems; i++){
if(stringCFG[i] == '>'){
RHS= 1;
}
...
}
BTW: Since you want to be able to add 4 extra chars, you probably should do:
char stringCFG[200]; --> char stringCFG[200 + 4];
BTW: Hard-coding the value 200 over and over again is bad practice. Instead use a define like:
#define MAX_CHARS 200
and replace all the hard-coded 200 with MAX_CHARS. Then you can adjust the maximum simply by editing one line instead of multiple lines.
Redistribute spaces in a fixed-size array of characters
Redistribute spaces in a fixed-size array of characters
I was given this problem during a g00gle interview last year (hint hint). I didn't pass that round, but I recently coded up my solution and was wondering if this is right, or if there's a better solution? Thanks!
Question:
Input: fixed-size array of characters, containing:
- 0 or more leading spaces
- 0 or more words separated by 1 or more spaces
- 0 or more trailing spaces
Output: the same array where spaces are re-distributed between the words in such a way that they are:
- no more leading spaces
- no more trailing spaces
- roughly the same space gaps between the words. I.e. the minimum and the maximum number of spaces between the words can not differ by more than 1.
Restriction: in-place algorithm. Do not use additional space for copying the characters.
Example:
- Input: "....word1.....word2.....word3....."
- Output: "word1.........word2..........word3"
- Gaps: 10 and 9
My solution: (I do notice that since string is immutable in python, my solution is not in-place?)
# remove leading and trailing spaces
s = raw_input()
orig_len = len(s)
s = s.strip(" ")
new_len = len(s)
# find indices of non-space chars
indices = [i for i in range(new_len) if s[i] != ' ']
num_spaces = orig_len - len(indices)
# find indices of start and end of words
start_indices = [indices[i] for i in range(1, len(indices)) if indices[i] != (indices[i-1] + 1)]
start_indices = [0] + start_indices
end_indices = [indices[i] for i in range(len(indices)-1) if indices[i+1] != (indices[i] + 1)]
end_indices = end_indices + [indices[-1]]
intervals = zip(start_indices, end_indices)
num_words = len(intervals)
spaces_each = num_spaces / (num_words - 1)
extra = num_spaces % (num_words - 1)
adjust = 0
for i in range(num_words-1):
end_of_prev = intervals[i][1]
start_of_next = intervals[i+1][0]
gap = start_of_next - end_of_prev - 1
if extra > 0:
if gap != spaces_each + 1:
s = s[:end_of_prev+1+adjust] + (spaces_each + 1) * ' ' + s[start_of_next+adjust:]
adjust = adjust + spaces_each + 1 - gap
extra = extra - 1Redistribute spaces in a fixed-size array of characters
Redistribute spaces in a fixed-size array of characters
I was given this problem during a g00gle interview last year (hint hint). I didn't pass that round, but I recently coded up my solution and was wondering if this is right, or if there's a better solution? Thanks!
Question:
Input: fixed-size array of characters, containing:
- 0 or more leading spaces
- 0 or more words separated by 1 or more spaces
- 0 or more trailing spaces
Output: the same array where spaces are re-distributed between the words in such a way that they are:
- no more leading spaces
- no more trailing spaces
- roughly the same space gaps between the words. I.e. the minimum and the maximum number of spaces between the words can not differ by more than 1.
Restriction: in-place algorithm. Do not use additional space for copying the characters.
Example:
- Input: "....word1.....word2.....word3....."
- Output: "word1.........word2..........word3"
- Gaps: 10 and 9
My solution: (I do notice that since string is immutable in python, my solution is not in-place?)
# remove leading and trailing spaces
s = raw_input()
orig_len = len(s)
s = s.strip(" ")
new_len = len(s)
# find indices of non-space chars
indices = [i for i in range(new_len) if s[i] != ' ']
num_spaces = orig_len - len(indices)
# find indices of start and end of words
start_indices = [indices[i] for i in range(1, len(indices)) if indices[i] != (indices[i-1] + 1)]
start_indices = [0] + start_indices
end_indices = [indices[i] for i in range(len(indices)-1) if indices[i+1] != (indices[i] + 1)]
end_indices = end_indices + [indices[-1]]
intervals = zip(start_indices, end_indices)
num_words = len(intervals)
spaces_each = num_spaces / (num_words - 1)
extra = num_spaces % (num_words - 1)
adjust = 0
for i in range(num_words-1):
end_of_prev = intervals[i][1]
start_of_next = intervals[i+1][0]
gap = start_of_next - end_of_prev - 1
if extra > 0:
if gap != spaces_each + 1:
s = s[:end_of_prev+1+adjust] + (spaces_each + 1) * ' ' + s[start_of_next+adjust:]
adjust = adjust + spaces_each + 1 - gap
extra = extra - 1